Hypothetical Example: if Rockets, Spurs Clipper Griz all tied with 55 wins, Rockets 3-1 against Clipper but 0-4 against everyone else Clipper is 1-3 against Rockets and 3-1 or 2-2 against everyone else so the seeding up end up like this 1. warrior 2. griz 3. clipper 4. blazers (division winner) 5. spurs 6. rockets 7. mavs 8. OkC Since rockets and clipper have same win, it goes to head to head(3-1), which means rockets will have home court against clipper? Am i right or wrong?
Let me clarify 1. Warrior 65 win 2. Griz 55 win 3. Clip 55 win 4. Blazers 53 win (Division Winner) 5. Spurs 55 win 6. Rockets 55 win 7. Mavs. 51 wins 8. OKC 46 wins Rockets Griz Clip Spurs all tied, so we used head to head of all the teams involved Rockets: 3-1 against clippers but 0-4 against everything else puts them at 3-9 Griz: 4-0 Rockets, 3-1 Spurs, 2-2 Clippers puts them at 9-3 Spurs: 4-0 Rockets, 1-3 Griz 0-4 against Clips puts them 5-7 Clip: 1-3 against Rockets, 4-0 against Spurs 2-2 against Griz puts them at 7-5 So Griz gets 2nd seed, Clipper 3rd, Spurs 5th and Rockets 6th But since Rockets are 3-1 against Clipper, do they get home court against Clipper in a 3-6 match up?
we are 2-2 against both the clippers and Grizz... and so far against the Spurs we are 1-1 against the Spurs with 2 games remaining. not sure what you are trying to say bro
First tiebreaker is actually the division winner. #1 Southwest would automatically be seeded higher than #2 Pacific. So you'd do a tiebreaker between Memphis, Houston, and San Antonio (leaving out the Clippers) to figure out who wins the division. Then you'd do another tiebreaker among the 2 remaining teams plus the Clips to figure out the 3rd seed. Another tiebreaker between the 2 remaining teams to figure out the 5th and 6th seed. The team with the better record gets HCA regardless of seed. In your scenario, which has already been pointed out as incorrect, I would assume that the Rockets would get HCA.
OP, First you have to establish the division winner of the Southwest, between HOU, MEM and SAS...that is based on best winning % of the three teams...as first tiebreaker The division winner gets removed from the equation Then, if there are still more than two teams tied, winning % of the remaining teams is again first tie-breaker. and so on.
Well in my scenario, Griz would be division winer so they get #2. Then Clipper would get 3rd seed because they are 5-3 against Rockets and Spurs Spurs would get 5th, 4-4 against Rockets and Clipper Rockets would get 6th, 3-5 against Spurs and Clipper Then we do head to head again to see who get home court between Clipper and Rockets. That means Rockets would get it since they are 3-1.
The division winner between Griz, Spurs, Rockets would have to be determined first. Then the tie would be broken between the 3 other teams.
As others have explained, you have to remember your order of operations: 1) Determine the three division winners. Use two team or multiple team tie break procedures to break ties. 2) Determine the winningest team that didn't win their division. Use two team or multiple team tie break procedures to break ties. 3) Seed the 4 teams from steps 1 and 2 using two team and multiple team tie breaks to break ties. Division winners automatically win the tie break over the team that didn't win their division. 4) Seed 5-8 based on record, using two team or multiple team tie breaks to break ties. 5) Home court in each round is given to the team with the best record. Two team tie breaks are used to break a tie, but a division winner automatically wins over a team that didn't win their division.
No. Clips would have already won the tiebreaker to get the 3 seed. It doesn't revert back to the tiebreaker again. Clips would have homecourt.