It's an identity; no real solution to z. Multiply both sides of y = z - x/y by y and you get y^2 = zy - x. Subtract zy from both sides and you get y^2 - zy = -x Isolate the extra y on the left and you get y(y - z) = x. 0(0 - z) = 0, means z could equal any number and you'd still get the same f(z).
"If you're leading your life in such a way that you never have to do math, congratulations, you are a donkey." - Maddox
I don't understand why people keep saying this. Any interger divided into ZERO PARTS .. IS ZERO Hehe I think a lot of math majors neglect to also study logic
What logic tells me is that if you are dividing by zero you are not dividing at all so is that a problem to be solved? So I can see the undefined reference.
What is an integer divided into 0.5 parts according to your logic? 0.5, or twice the original number?
y = z - x/y where y=0, z=0. what is x? Rarely do most math folks insert the values before simplifying the equation... y - z = -x/y y(y-z) = -x y^2- yz = -x x = - (y^2 - yz) x = - (0^2 - 0*0) x = 0 by the rules of PEMDAS(aka order of operations)...you have to do it this way first....Parentheses, exponents, multiplication, division, addition and subtraction...This why the answer is zero and not undefined...
This is exactly what I think .. Who puts in values before isolating the variable that they want to solve for ? We have people talking about finer theories of mathematics, but if you just do it this way the answer is clear cut.
y=z - x/y 0=0 -x/0 0=0 - (x/0) cannot divide by 0. Impossible to answer. or y=z - x/y y^2=z-x (0x0=0) = 0-x 0=0-x x=0
Really? I am only going to a community college but every single math course I have been in, if you are given a value, you plug it in.
Brilliant. IF you want to get around undefined values, just use a variable briefly to get rid of it, then go on with your day. Let a=b a^2 = ab 2(a^2) = a^2 + ab 2(a^2) - 2ab= a^2 + ab - 2ab 2(a^2 - ab) = a^2 - ab 2 = 1
