Mazie counted her dimes. When she put them in groups of 4, she had 2 dimes left over. When she put them in groups of 5, she had one left over. What is the smallest number of dimes she could have, if she has more than 10? I know the answer, it doesn't take a lot of trial and error or intuition, but I can't figure out what the equation to solve would be. I was thinking it would be: X/4+2 = X/5+1 but A. I'm too old to reduce it to X and B. I also don't think it's right now.
I think your equation would actually be x/4 - 2 = x/5 -1. Find a common denominator and multiply both sides of the equation by it to get rid of the fraction. Common denominator for 4 and 5 is 20 so if you multiply both sides of the equation by 20 you get: 5x - 40 = 4x - 20 Subtract 4x from both sides to get x - 40 = -20 Add 40 to both sides to get x = 20 On the surface that answer makes sense to me but it has been a LOOOOOONG time since I have done an algebraic word problem like this. EDIT - Hmm, in re-reading the problem, I think the answer would actually be 46, but I don't know how to put it in an equation form either, LOL.
That's a bit odd, because when I put in the equation x/4 + 2 = x/5 + 1, I get 20, which isn't the right answer because when you put 20 into groups of 5, you get a whole number (4), so no remainders.
X = the number of dimes Maizie has The answer is 26, 26 is 4 stacks of 6 +2 or 5 stacks of 5 +1 I just don't have a clue about a formula. Mine is wrong.
This equation may be a start - it gets you an answer, but that answer is 6 (which would be right if you were allowed to have less than 10.) (x-2)/4 = (x-1)/5 Are we morons?
x>10 4x+2=5x+1 4x+2-2=5x+1-2 4x=5x-1 okay that's where I'm stuck! LOL edit.. okay that is so wrong... lemme try again (x-2)/4=(x-1)/5 common denomenator? okay I am an idiot cause I can't get this either... where's the guy who had the formula in his sig??
Atually the equation is 5x+1 = 4y+2 =Z so X=(4y+1)/5 and X,Y have to be a positive integer and Z > 10. It is pretty easy to see Y=6 to make X= (4x6 +1)/5 = 5 so total is 5x5 +1 = 4x6 +2 = 26
Oh, I see. So how do you enforce x>20? It's like a health insurance mandate, or a law outlawing abortion.
you should really put this in the GARM. Not being racist or ethnocentric, but there was a 5 page thread about a math problem and people were getting seriously pissed at each other over it.
We must be morons. But it says that it is divided into a group of 4 or 5 with remainder 1 or 2, so I think the equation should be: 4x+2 = Total number of dimes. 5y+1 = Total number of dimes. Damnit, and to think I came 4th in the entire year in Maths.
These two are unrelated at the beginning. So you say 4a + 2 = x>10 5b + 1 = x>10 Then find the lowest common denominator. 4(3) +2 = 14 4(4) +2 = 18 4(5) +2 = 22 4(6) +2 = 26 5(2) + 1 = 11 5(3) + 1 = 16 5(4) + 1 = 21 5(5) + 1 = 26 26 is your lowest common denominator. your multiples are 5 and 6 Your equations now become 4a + 2 = 26 5b + 1 = 26 so 6 and 5 are the uh... least common multiples or whatever. so you insert 6 in the first equation and 5 in the 2nd. 4a + 2 = 26 a= 6 4(6)+2 = 26 5b + 1 = 26 b = 5 5(5)+1 = 26 She had 6 groups of 4 and 5 groups of 5 (Edit - the other steps were pretty much unnecessary)
Finally, thanks moestavern19, and you used that simply denomination thing that I had totally forgotten about......and my 9 year old sister is currently learning. I think I may need to go back to grade school maths.
He didn't say they were using graph paper but you might have to plot (x-2)/4 and (x-1)/5 where X-1 is greater than 10
I think just this much is enough, I did that part in my head, I didn't know that this was an actual math process (Denominations?) I said 5th grader but my great nephew is only 9 also, I just didn't want to embarass myself.
