My nephew is taking algebra and I have forgotten everything I learned about algebra as I no longer have any use for it. lol Here is the problem..... (4x^3y^-3)^2 (3x^-2y^-1)^2 __________________________ (5x^0y^-2)^2 (5x^2y)^2 those with the ^ are exponents like x^3 i simplified it to (16x^6y^-6) (9x^-4y^-2) _______________________ (25x^0y^-4) (25x^4y^2) i further simplified it to 144x^2y^-8 ____________ 625x^4y^-2 now after that im stuck. 1. Did i simplify it right in the steps i did? 2. How do i further simplify?
Quotient Rule 2-4 = -2 = x-2 -8-(-2) = y-6 You will have to flip or rearrange it some how because of the negative exponents but I'm not quite sure what the end result will be.
That's supposed to be x to the negative 2 and y to the negative 6. Also, anybody with algebra expertise can correct my mistakes if I am wrong.
Assuming you got to this part right: 144x^2y^-8 ____________ 625x^4y^-2 then you do this (144/625)(x^(2-4))(y^(-8--2))=(144/625)(X^-2)(Y^-6)
That's what I posted. I think it (final answer) would be: 144 -------- 625x^2y^6 Anybody care to back me up?
