are you smart ?read the two old intelligence questions ! maby someone read these ever and these are not too hard. 1. one young man is abducted by terror. terror boss take him to a big house ,and then the young man face to two doors ,each door is guarded by a terr . boss say to him "you maby die maby live.one door lead to die and another door lead to alive,you must choose one door to enter. and now as you look ,there are two guarders,one guarder only speak truth and another one only speak flam.now i dont know who guard which door too.you can ask just only one question to them.go! " certainly the young man is not rambo ,hence he choose one guarder and ask him a question .after getting the answer ,the young man enter one of the doors and survive! now this question:how did the young man ask? 2. we have ten apples ,9 apples is same weight and another one's weight is different.we dont know the different apple is weighter or lighter . now give you a scale . questionlease find out the different apple and use the scale just 3 times. forgive for my poor english.i wish get the answer of smart you.
1. He asked the guard, "What door would the other guard tell me to go through to live?" and then he went through the opposite door. explaination: The guard who tells the truth will say that the other guard always lies so he will tell you to go through the door that leads to death not life when you ask which door leads to life. (So he chooses the opposite) The guard who always lies will lie and say that the guard who tells the truth will also tell you to good through the door that leads to death. So always choose the door they say the other will lead to death.
1 apple = * **** **** on the first scale, have ** on your hand. whichever side the scale tips, you have a heavy *. If it doesn't tip, you have heavy * on your hand. ** ** on the second weighing... Blah blah... yadda yadda... Mr. JJ-Ryu-Lee, you have good tests. Too bad this thread may be too short.
I thought that too but the problem with the answer is that you are assuming the odd apple is heavier. If it is lighter, and on the scale in a group of four, then when you break the heavier group into groups of 2 they will be equal. you'll have to use the scale 4 times to find the apple that way.
1) Benvolio beat me to it. 2.) weigh 5 on one side of the scale and 5 on the other. Whichever sight is lighter, remove those five. Of those five apples which weren't removed... weigh 2 on one side of the scale and 2 on the other. If both are the same weight, the apple which wasn't weighed is heavier apple. Otherwise remove the two apples from the lighter side - neither of them is the heavy apple, nor is the one which wasn't weighed. Of those two apples which weren't removed... weigh 1 on one side of the scale and 1 on the other. whichever one tips the scale down is the heavier apple. -- droxford
Apples. Weigh 3 on each side, 4 in your hand. 1. If they come out even, discard those 6. 1B.Weigh 3 of the remaining vs. 3 of the discards. If even, you have 9 discards. Weigh remaining vs. discard and you know if it's light of heavy. 1C. BUT IF when you weighed 3 vs. 3 discards and it didn't come out even, which way did it tip, heavy or light? (Discard 1 never weighed, for 7 discards.) Then weigh 2 of those remaining against each other. If they're even, then the unweighed one is either heavy or light, depending on how the 3 went against 3 discards. If they're unmatched, you know which one is either heavy or light depending on how they weighed against the 3 discards. 2. If they come out uneven, discard the 4 you never weighed. 2B. Weigh heavy side again vs. 3 of your discards. If it's even, you have 1 light apple. Weigh 2 of the light side against eachother. If they're even, the remaining 1 is light; if they're not even, the light is the one you want. 2C. Weigh the heavy side again vs. 3 discards. If it's uneven, you have 1 heavy. Weigh 2 of the heavys against each other. If they're even, the remaining 1 is heavy; if they're not, the heavy one is the one you want.
Okay, I know some of you have already posted the answer but I swear that I didn't look. I want to get this on my own. 1. Thinks for a long time, then gives up. Sigh. 2. I had to puzzle over this one for a while. But I actually got it. I'm going to number the apples to make it clearer. First off weigh a total of six of the apples against each other like this: 1, 2, 3 against 4, 5, 6 If they balance then none of these apples is the right one. Next you weigh: 7 against 8 If they balance then you weigh 9 against 2 If they balance then #10 is the right apple. If they don't balance then you know that #9 is the right apple. You can choose any apple between #1-8 but I just chose #2. If however 7 and 8 didn't balance, then you weigh: 7 against 2. If they balance, then #8 is the right apple. If they don't balance then yadda, yadda, yadda #7. Going back, if 1, 2, 3 doesn't balance with 4, 5, 6 then you: Take 1 and 4 off the scale, and switch #2 and 5 so: 5, 3 against 2, 6 If they balance, then do: 1 against 9 If they balance then it's #4 otherwise #1. If 5, 3 against 2, 6 don't balance and weight got shifted from one side to another then: 5 against 9 If they balance then it's #2 otherwise #5. If 5,3 against 2, 6 don't balance but the weight did not shift from one side to the other then: 3 against 9 If they balance then it's #6 otherwise #3. I know it seems like a lot of weighing, but it's all "if's". This tactic fulfills the 3 scale restriction. Whew, that was a pretty tough problem. I sure hope my explanation was clear enough.
2) Pick out any 2 apples Weigh each of the 2 separately Weigh all the apples together Do the simple math and find the weigh of each one
