Does anyone know how the tie breaker for the lottery is determined between the 2nd and 3rd worst record?
The odds are averaged out in the event of a tie, but in the case of 2/3, the odds are the same. After that, it's done randomly -- so the equivalent of a coin toss to decide which team is ahead of the other in the event they both come up short of the top 4.
Nope. Per Clutch, if we are unlucky on lottery night then a coin flip could land us at #7 which would be disheartening after painfully watching every single loss this year with the only positive being that we’d be selecting 1-5 in the draft.
The angle is important. I would say a strong FO drafting would be confident with a 7th pick. Curry was drafted 7th, Franz Wagner was 8th.
Of course nothing is ever guaranteed in the draft which is why having a strong FO is great like you said. The whole point of the debate around the forums is that you don't want to risk getting the 7th pick when the guy who you really want (who you might identify as the top prospect) gets taken 5th of 6th. That's the jist of it really. Hopefully it won't come to that and we finally get the 1st for our 3 years of bad play.
A strong front office would also prefer the position two spots earlier for 2 more options and trade potential, and wouldn't screw around with meaningless wins, because a strong front office has common sense.
Bro, that is true but the premise of the thread was “who do we take at #7 IF we pick 7th”. Never guaranteed anything. 14% 1-3 generates the question of who should we take, so it’s fair to ask 7% #7 who we would take.