This is the problem: I'm having trouble figuring this out. Anyone able to help would be much appreciated.
P(A) = accounting = 0.4 P(B) = statistics = 0.5 P(A and B) = both = 0.3 P(A or B) = P(A) + P(B) - P(A and B) = in accounting or statistics or both = 0.4 + 0.5 - 0.3 = 0.6
shouldn't the 1st three just be 40,50,30? I think the last one should be 60. But could be completely wrong because that seems too obvious. What level of math are you doing?
Thanks for the feedback guys. This is actually a review for a statistics class. I guess I was trying to read too much into the problem that I didn't realize the first 3 were that simple.
Its a review for a Quantitative Methods for Management class (class after Statistics). I took Stats last fall so I'm brushing up on old concepts. I've always hated these type of probability questions.
The answers to the first 3 questions are already given to you in the problem. If 30% are in both and 40% are in accounting, than 10% are in accounting but not statistics.. If 30% are in both and 50% are in statistics, than 20% are in statistics but not accounting. P(statistics or accounting) = P(statistics but not accounting) + P(accounting but not statistics) + P(statistics and accounting) = P(statistics) + P(accounting) - P(statistics and accounting)
This although I did quickly in head might have skipped a step if there was a trick question ....but pretty basic the info is all given to ya there
Meh, you should be asking and solving questions like these 1) What is the probability that 2 randomly chosen students are classmates in either the accounting class or the statistics class? Assuming student size is large (>1000). 2) What is the probability that 2 out of 3 randomly chosen students are classmates in either the accounting class or the statistics class? Assuming student is large (>1000).
