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theogcasey is offline Old 02-22-2010, 09:08 PM   #1
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Need help with chem 2. Hopefully someone has an idea...

Calculate the vapor pressure (in torr) at 310 K in a solution prepared by dissolving 23.8 g of the non-volatile non-electrolyte sucrose in 126 g of water. The vapor pressure of water at 310 K is 47.08 torr.

Thanks.

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Egghead is offline Old 02-22-2010, 09:17 PM   #2
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sorry I cant help... you should try posting this on yahoo answers
 
Bandwagoner is offline Old 02-22-2010, 09:19 PM   #3
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Quote:
Originally Posted by theogcasey
Need help with chem 2. Hopefully someone has an idea...

Calculate the vapor pressure (in torr) at 310 K in a solution prepared by dissolving 23.8 g of the non-volatile non-electrolyte sucrose in 126 g of water. The vapor pressure of water at 310 K is 47.08 torr.

Thanks.
http://en.wikipedia.org/wiki/Raoult's_law

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justtxyank is offline Old 02-22-2010, 09:19 PM   #4
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If you want to help chemistry you need to dump the oft-injured cancer. It's hard to focus when you have a whining petulant child clouding the future of your organization.
 
Bandwagoner is offline Old 02-22-2010, 09:21 PM   #5
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Crap! Why did I help you? i just realized I hate you. You stole my name. I am the OG casey as you can clearly see from my join date

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Xcellerator is offline Old 02-22-2010, 09:22 PM   #6
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P = X solvent * P solvent
X solvent = moles of solvent/total moles
Molar mass of water = 18 g/mol
Moles of solvent (water) = 126/18 = 7 moles

Molar mass of sucrose = 342.3 g/mol
Moles of solute (sucrose) = 23.8g/342.3 = .06953

Total moles = 7.06953 moles

X solvent = moles of water/total moles = 7 mol/7.06952 mol = .990166

P = X solvent * P solvent = .990166 * (47.08 torr) = 46.617 ~ 46.6 torr (3 sig figs)

Hope that's right. Just had a test over it along with other stuff.
 
theogcasey is offline Old 02-22-2010, 09:26 PM   #7
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Quote:
Originally Posted by Xcellerator
P = X solvent * P solvent
X solvent = moles of solvent/total moles
Molar mass of water = 18 g/mol
Moles of solvent (water) = 126/18 = 7 moles

Molar mass of sucrose = 342.3 g/mol
Moles of solute (sucrose) = 23.8g/342.3 = .06953

Total moles = 7.06953 moles

X solvent = moles of water/total moles = 7 mol/7.06952 mol = .990166

P = X solvent * P solvent = .990166 * (47.08 torr) = 46.617 ~ 46.6 torr (3 sig figs)

Hope that's right. Just had a test over it along with other stuff.
Thanks a bunch! I accidentally used the moles of sucrose instead of water... Dumb.

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Xcellerator is offline Old 02-22-2010, 09:29 PM   #8
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Quote:
Originally Posted by theogcasey
Thanks a bunch! I accidentally used the moles of sucrose instead of water... Dumb.
Well, if you use moles of sucrose, you can subtract its torr from the water torr and still get the answer.
 
kikimama is offline Old 02-22-2010, 09:43 PM   #9
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Quote:
Originally Posted by Xcellerator
Well, if you use moles of sucrose, you can subtract its torr from the water torr and still get the answer.
yeah but the solenoids of the thearcheia won't be viable
 

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